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प्रश्न
164, 160, 156, 152, ...... are in Arithmetic Progression (A.P.). Find:
- which term is equal to 0.
- the sum of its first 20 terms.
योग
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उत्तर
Here $$a = 164, \ d = -4$$.
i. Let the nth term be 0:
$$164 + (n - 1)( - 4) = 0$$
$$\Rightarrow 168 - 4n = 0$$
$$\Rightarrow n = 42$$
So the 42nd term is 0.
ii. $$S_{20} = \frac{20}{2}[2(164) + 19(-4)]$$
$$= 10(328 - 76)$$
$$= 2520$$
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