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प्रश्न
15 cards, numbered 1, 2, 3...., 15 are put in a box and mixed thoroughly. A card is drawn at random from the box. Find the probability that the card drawn bears a number divisible by 2 or 3.
योग
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उत्तर
Given:15 cards numbered 1, 2,...,15 are equally likely; one card is drawn at random.
Step-wise calculation:
1. Total number of outcomes = 15.
2. Numbers divisible by 2 or 3:
Multiples of 2: 2, 4, 6, 8, 10, 12, 14 (7)
Multiples of 3: 3, 6, 9, 12, 15 (5)
Multiples of both 2 and 3 i.e., 6: 6, 12 (2)
Using inclusion–exclusion:
Favourable = 7 + 5 – 2
= 10
Probability = `10/15`
= `2/3`
Probability the card shows a number divisible by 2 or 3 = `2/3`.
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अध्याय 22: Probability - Exercise 22A [पृष्ठ ५०५]
