Question

12ⁿ cannot end with the digit 0 or 5 for ______ value of n.

Answer 1

12ⁿ cannot end with the digit 0 or 5 for any value of n.

Explanation:

If a number ends with 0 or 5 it must be divisible by 5. But 12ⁿ = (2² × 3)ⁿ = 2²ⁿ × 3ⁿ has only prime factors 2 and 3 (no factor 5), so it can never be divisible by 5 and therefore cannot end with 0 or 5 for any natural number n.