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प्रश्न
104g of water at 30°C is taken in a calorimeter made of copper of mass 42 g. When a certain mass of ice at 0°C is added to it, the final steady temperature of the mixture after the ice has melted, was found to be 10°C. Find the mass of ice added. [Specific heat capacity of water = 4.2 Jg–1°C–1 ; Specific latent heat of fusion of ice = 336 Jg–1; Specific heat capacity of copper = 0.4 Jg–1°C–1] .
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उत्तर
mw =104g
Tw = 30° C
mc = 42 g
T =10°C
mi = ?
By Calorimetry,
Heat lost = Heat gained
mw Sw(Tw -T) + mc Sc(Tw - T) =mi α + mi Sw(T-Ti)
⇒ (104)(4.2)(30 -10) +(42)(0.4)(30 -10) = mi (336)+ mi(4.2)(10- 0)
⇒ mi `=((104)(4.2)(20)+(42)(0.4)(20))/((336+42)) = 24 g`
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संबंधित प्रश्न
What do you understand by the following statements:
The specific heat capacity of lead is 130 Jkg-1K-1.
Water boils at 120 °C in a pressure cooker. Explain the reason.
A vessel of negligible heat*capacity contains 40g of ice in it at 0°C, 8g of steam at 100°C is passed into the ice to melt it. Find the final temperature of the contents of the vessel.
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Numerical Problem.
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