Advertisements
Advertisements
प्रश्न
10 cubic metres clay is uniformly spread on a land of area 10 ares. the rise in the level of the ground is
विकल्प
1 cm
10 cm
100 cm
1000 cm
Advertisements
उत्तर
Volume of the clay to be spread,
V = 10 m3
Area on which the clay is spread
A = 10 are
= 1000 m2
Let,
h → Rise in the level of the ground
We know that,
V = A × h
`h = V/A`
` = 10/1000`
= 0.01 m
= 0.01 × 100 cm
= 1 cm
Rise in the level of the ground is 1 cm .
APPEARS IN
संबंधित प्रश्न
There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?
![]() |
![]() |
| (a) | (b) |
Find the height of a cuboid whose base area is 180 cm2 and volume is 900 cm3?
A cuboidal vessel is 10 cm long and 5 cm wide. How high it must be made to hold 300 cm3 of a liquid?
Find the volume in cubic metre (cu. m) of the cuboid whose dimensions is length = 10 m, breadth = 25 dm, height = 50 cm.
A cuboidal box is 5 cm by 5 cm by 4 cm. Find its surface area.
Show that the product of the areas of the floor and two adjacent walls of a cuboid is the square of its volume.
A field is 150 m long and 100 m wide. A plot (outside the field) 50 m long and 30 m wide is dug to a depth of 8 m and the earth taken out from the plot is spread evenly in the field. By how much is the level of field raised?
Find the volume and the total surface area of a cuboid, whose :
length = 15 cm, breadth = 10 cm and height = 8 cm.
Three cubes each of side 10 cm are joined end to end. Find the surface area of the resultant figure.


