Question

\[\frac{1 - \tan^2 45°}{1 + \tan^2 45°}\] is equal to 

विकल्प

• tan 90° 

• 1

• sin 45° 

• sin 0°  

Answer 1

We have to find the value of the following 

`(1- tan^2 45°)/(1+tan^2 45°)`

so 

`(1-tan^2 45°)/(1+tan^2 45°)` 

=`(1-(-1)^2)/(1+(1)^2)`

=`0/1`

=` 0` 

We know that tan `45°=1`

              ` sin 0°=0`

= `sin 0°`