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प्रश्न

\[\int\limits_0^1 \frac{1}{1 + x^2} dx\]
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उत्तर

\[Let I = \int_0^1 \frac{1}{1 + x^2} d x . Then, \]
\[I = \left[ \tan^{- 1} x \right]_0^1 \]
\[ \Rightarrow I = \tan^{- 1} 1 - \tan^{- 1} 0\]
\[ \Rightarrow I = \frac{\pi}{4} - 0\]
\[ \Rightarrow I = \frac{\pi}{4}\]

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Definite Integrals
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 20: Definite Integrals - Exercise 20.1 [पृष्ठ १६]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 20 Definite Integrals
Exercise 20.1 | Q 4 | पृष्ठ १६

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