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R.S. Aggarwal solutions for Mathematics [English] Class 6 chapter 6 - Simplification [Latest edition]

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Chapters

    1: Number System

    2: Factors and Multiples

    3: Whole Numbers

    4: Integers

   Chapter 5: Fractions

▶ 6: Simplification

    7: Decimals

    8: Algebraic Expressions

    9: Linear Equation in One Variable

    10: Ratio, Proportion and Unitary Method

   Chapter 11: Line Segment, Ray and Line

   Chapter 12: Parallel Lines

   Chapter 13: Angles and Their Measurement

   Chapter 14: Constructions (Using Ruler and a Pair of Compasses)

   Chapter 15: Polygons

   Chapter 16: Triangles

   Chapter 17: Quadrilaterals

   Chapter 18: Circles

   Chapter 19: Three-Dimensional Shapes

   Chapter 20: Two-Dimensional Reflection Symmetry (Linear Symmetry)

   Chapter 21: Concept of Perimeter and Area

   Chapter 22: Data Handling

   Chapter 23: Pictograph

   Chapter 24: Bar Graph

R.S. Aggarwal solutions for Mathematics [English] Class 6 chapter 6 - Simplification - Shaalaa.com
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Solutions for Chapter 6: Simplification

Below listed, you can find solutions for Chapter 6 of CBSE R.S. Aggarwal for Mathematics [English] Class 6.


Exercise 6AExercise 6BTest Paper 6
Exercise 6A [Page 107]

R.S. Aggarwal solutions for Mathematics [English] Class 6 6 Simplification Exercise 6A [Page 107]

Exercise 6A | Q 1 | Page 107

Simplify:

21−12 ÷ 3 × 2
Exercise 6A | Q 2 | Page 107

Simplify:

16+8÷4−2×3
Exercise 6A | Q 3 | Page 107

Simplify:

13−(12−6÷3)
Exercise 6A | Q 4 | Page 107

Simplify:

19−[4+16−(12−2)]
Exercise 6A | Q 5 | Page 107

Simplify:

36−[18−14−(15−4÷2×2)]
Exercise 6A | Q 6 | Page 107

Simplify:

27−[18−16−(5−`overline(4−1)`)]
Exercise 6A | Q 7 | Page 107

Simplify:

\[4\frac{4}{5} \div \frac{3}{5} \text{ of } 5 + \frac{4}{5} \times \frac{3}{10} - \frac{1}{5}\]
Exercise 6A | Q 8 | Page 107

Simplify:

\[\left( \frac{2}{3} + \frac{4}{9} \right) \text{ of }\frac{3}{5} \div 1\frac{2}{3} \times 1\frac{1}{4} - \frac{1}{3}\]
Exercise 6A | Q 9 | Page 107

Simplify:

\[7\frac{1}{3} \div \frac{2}{3}\text{ of }2\frac{1}{5} + 1\frac{3}{8} \div 2\frac{3}{4} - 1\frac{1}{2}\]
Exercise 6A | Q 10 | Page 107

Simplify:

\[5\frac{1}{7} - \left\{ 3\frac{3}{10} \div \left( 2\frac{4}{5} - \frac{7}{10} \right) \right\}\]
Exercise 6A | Q 11 | Page 107

Simplify:

\[9\frac{3}{4} \div \left[ 2\frac{1}{6} + \left\{ 4\frac{1}{3} - \left( 1\frac{1}{2} + 1\frac{3}{4} \right) \right\} \right]\]
Exercise 6A | Q 12 | Page 107

Simplify:

\[4\frac{1}{10} - \left[ 2\frac{1}{2} - \left\{ \frac{5}{6} - \left( \frac{2}{5} + \frac{3}{10} - \frac{4}{15} \right) \right\} \right]\]
Exercise 6A | Q 13 | Page 107

Simplify:

\[1\frac{5}{6} + \left[ 2\frac{2}{3} - \left\{ 3\frac{3}{4} \left( 3\frac{4}{5} \div 9\frac{1}{2} \right) \right\} \right]\]
Exercise 6A | Q 14 | Page 107

Simplify:

\[4\frac{4}{5} \div \left\{ 2\frac{1}{5} - \frac{1}{2}\left( 1\frac{1}{4} - \overline{\frac{1}{4} - \frac{1}{5}} \right) \right\}\]
Exercise 6A | Q 15 | Page 107

Simplify:

\[7\frac{1}{2} - \left[ 2\frac{1}{4} \div \left\{ 1\frac{1}{4} - \frac{1}{2}\left( \frac{3}{2} - \overline{\frac{1}{3} - \frac{1}{6}} \right) \right\} \right]\]
Exercise 6B [Page 108]

R.S. Aggarwal solutions for Mathematics [English] Class 6 6 Simplification Exercise 6B [Page 108]

Exercise 6B | Q 1 | Page 108

8 + 4 ÷ 2 × 5 = ?

  • 30

  • 50

  • 18

  • none of these

Exercise 6B | Q 2 | Page 108

54 ÷ 3 of 6 + 9 = ?

  • 117

  • 12

  • `6/5`

  • none of these

Exercise 6B | Q 3 | Page 108

13 − (12 − 6 ÷ 3) = ?

  • 11

  • 3

  • `7/3`

  • none of these

Exercise 6B | Q 4 | Page 108

1001 ÷ 11 of 13 =?

  • 7

  • 1183

  • 847

  • none of these

Exercise 6B | Q 5 | Page 108

133 + 28 ÷ 7 − 8 × 2 = ?

  • 7

  • 121

  • 30

  • none of these

Exercise 6B | Q 6 | Page 108

3640 − 14 ÷ 7 × 2 = ?

  • 3636

  • 1036

  • 1819

  • none of these

Exercise 6B | Q 7 | Page 108

100 × 10 − 100 + 2000 ÷ 100 = ?

  • 29

  • 920

  • none of these

Exercise 6B | Q 8 | Page 108

`27 - [18 - {16 - (5 -overline(4-1))}] = ? `

  • 25

  • 23

  • none of these

Exercise 6B | Q 9 | Page 108

\[32 - [48 \div {36 - (27 - \overline{{16 - 9}})}] = ?\]

  • 29

  • \[\frac{520}{17}\]
  • none of these

Exercise 6B | Q 10 | Page 108

8 − [28 ÷ {34 − (36 − 18 ÷ 9 × 8)}] = ?

  • 6

  • \[6\frac{4}{9}\]
  • none of these

Test Paper 6 [Page 109]

R.S. Aggarwal solutions for Mathematics [English] Class 6 6 Simplification Test Paper 6 [Page 109]

Test Paper 6 | Q 1 | Page 109

Simplify:

\[16 - [11 + {8 - 6 - \bar{{4 - 2}}}]\]
Test Paper 6 | Q 2 | Page 109

Simplify:

16 + 8 ÷ 4 − 2 × 3

Test Paper 6 | Q 3 | Page 109

Simplify:

\[36 - [18 - {14 - (15 - 4 \div 2 \times 2)}]\]
Test Paper 6 | Q 4 | Page 109
\[36 - [18 - {14 - (15 - 4 \div 2 \times 2)}]\]
  • 8

  • 2

  • 17

  • none of these

Test Paper 6 | Q 5 | Page 109
\[16 - 2 \div 7 + 6 \times 2 = ?\]
  • 16

  • 14

  • \[27\frac{5}{7}\]
  • none of these

Test Paper 6 | Q 6 | Page 109
\[\frac{28}{1} - \frac{2}{7} = \frac{\left( 196 - 2 \right)}{7} = \frac{194}{7} = 27\frac{5}{7}\]
  • 117

  • 12

  • \[\frac{6}{5}\]
  • none of these

Solutions for 6: Simplification

Exercise 6AExercise 6BTest Paper 6
R.S. Aggarwal solutions for Mathematics [English] Class 6 chapter 6 - Simplification - Shaalaa.com

R.S. Aggarwal solutions for Mathematics [English] Class 6 chapter 6 - Simplification

Shaalaa.com has the CBSE Mathematics Mathematics [English] Class 6 CBSE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics Mathematics [English] Class 6 CBSE 6 (Simplification) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. R.S. Aggarwal textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 6 chapter 6 Simplification are Mathematical Patterns, Patterns in Numbers, Patterns in Shapes.

Using R.S. Aggarwal Mathematics [English] Class 6 solutions Simplification exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.S. Aggarwal Solutions are essential questions that can be asked in the final exam. Maximum CBSE Mathematics [English] Class 6 students prefer R.S. Aggarwal Textbook Solutions to score more in exams.

Get the free view of Chapter 6, Simplification Mathematics [English] Class 6 additional questions for Mathematics Mathematics [English] Class 6 CBSE, and you can use Shaalaa.com to keep it handy for your exam preparation.

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