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HSC Science (Computer Science) इयत्ता १२ वी - Maharashtra State Board Question Bank Solutions for Mathematics and Statistics

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Mathematics and Statistics
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If x = cos θ and y = sin3θ, show that `y(d^2y)/(dx^2) + (dy/dx)^2` = 3sin2θ(5cos2θ – 1)

[8] Differentiation
Chapter: [8] Differentiation
Concept: undefined >> undefined

The negation of p ∧ (q → r) is ______________.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

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Without using truth tabic show that ~(p v q)v(~p ∧ q) = ~p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using the truth table show that P ↔ q ≡ (p ∧ q) ∨ (~ p ∧ ~ q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

If A = {2, 3, 4, 5, 6}, then which of the following is not true?

(A) ∃ x ∈ A such that x + 3 = 8

(B) ∃ x ∈ A such that x + 2 < 5

(C) ∃ x ∈ A such that x + 2 < 9

(D) ∀ x ∈ A such that x + 6 ≥ 9

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Rewrite the following statement without using if ...... then.

If a man is a judge then he is honest.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Rewrite the following statement without using if ...... then.

It 2 is a rational number then `sqrt2` is irrational number.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Rewrite the following statement without using if ...... then.

It f(2) = 0 then f(x) is divisible by (x – 2).

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

(p ∨ q) ∧ (p ∨ ∼ q) ≡ p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

(p ∧ q) ∨ (∼ p ∧ q) ∨ (p ∧ ∼ q) ≡ p ∨ q

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that:

∼ [(p ∨ ∼ q) → (p ∧ ∼ q)] ≡ (p ∨ ∼ q) ∧ (∼ p ∨ q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

p ↔ q ≡ ∼(p ∧ ∼q) ∧ ∼(q ∧ ∼p)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

∼p ∧ q ≡ (p ∨ q) ∧ ∼p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using rules in logic, prove the following:

∼ (p ∨ q) ∨ (∼p ∧ q) ≡ ∼p

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(p ∨ q) ∧ (q ∨ ∼r)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

p ∧ (q ∨ r)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(p → q) ∧ r

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Using the rules in logic, write the negation of the following:

(∼p ∧ q) ∨ (p ∧ ∼q)

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table prove that (p ∧ q) ∨ (∼ p ∧ q) v (p∧ ∼ q) ≡ p ∨ q

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined

Without using truth table, prove that : [(p ∨ q) ∧ ∼p] →q is a tautology.

[1] Mathematical Logic
Chapter: [1] Mathematical Logic
Concept: undefined >> undefined
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