Please select a subject first
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Long answer type question.
Derive an expression for strain energy per unit volume of the material of a wire.
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Answer the following.
Calculate the work done in stretching a steel wire of length 2 m and cross-sectional area 0.0225 mm2 when a load of 100 N is slowly applied to its free end. (Young’s modulus of steel = 2 × 1011 N/m2)
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Answer briefly.
State and explain the principle of superposition of waves.
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Solve the following problem.
Obtain a derivative of the following function: x sin x
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Solve the following problem.
Obtain derivative of the following function: x4 + cos x
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Solve the following problem.
Obtain derivative of the following function: `"x"/"sin x"`
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Solve the following problem.
Using the rule for differentiation for quotient of two functions, prove that `"d"/"dx" ("sin x"/"cos x") = sec^2"x"`.
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Solve the following problem.
Evaluate the following integral: \[\int_0^{\frac{\pi}{2}}\] sin x dx
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Solve the following problem.
Evaluate the following integral: \[\int_1^5\] x dx
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Answer in one sentence.
State the names of the hardest material and the softest material.
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Choose the correct option.
The maximum distance up to which TV transmission from a TV tower of height h can be received is proportional to
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Choose the correct option.
If a TV telecast is to cover a radius of 640 km, what should be the height of the transmitting antenna?
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Answer briefly.
What are EM waves?
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Answer briefly.
How are EM waves produced?
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Answer briefly.
How does the effective power radiated by an antenna vary with wavelength?
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Answer briefly.
Why should broadcasting programs use different frequencies?
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Solve the numerical problem.
In an EM wave, the electric field oscillates sinusoidally at a frequency of 2 × 1010 Hz. What is the wavelength of the wave?
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Solve the numerical problem.
A TV tower has a height of 200 m. How much population is covered by TV transmission if the average population density around the tower is 1000/km2? (Radius of the Earth = 6.4 × 106 m)
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Solve the numerical problem.
Height of a TV tower is 600 m at a given place. Calculate its coverage range if the radius of the Earth is 6400 km. What should be the height to get the double coverage area?
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The length, breadth, and thickness of a rectangular sheet of metal are 4.234 m, 1.005 m, and 2.01 cm respectively. Give the area and volume of the sheet to correct significant figures.
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