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Find Sn of the following arithmetico - geometric sequence:
1, 4x, 7x2, 10x3, 13x4, …
Concept: undefined >> undefined
Find Sn of the following arithmetico - geometric sequence:
1, 2 × 3, 3 × 9, 4 × 27, 5 × 81, …
Concept: undefined >> undefined
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Find Sn of the following arithmetico - geometric sequence:
3, 12, 36, 96, 240, …
Concept: undefined >> undefined
Find the sum to infinity of the following arithmetico - geometric sequence:
`1, 2/4, 3/16, 4/64, ...`
Concept: undefined >> undefined
Find the sum to infinity of the following arithmetico - geometric sequence:
`3, 6/5, 9/25, 12/125, 15/625, ...`
Concept: undefined >> undefined
Find the sum to infinity of the following arithmetico - geometric sequence:
`1, -4/3, 7/9, -10/27 ...`
Concept: undefined >> undefined
Find the sum `sum_("r" = 1)^"n" ("r" + 1)(2"r" - 1)`
Concept: undefined >> undefined
Find `sum_("r" = 1)^"n"(3"r"^2 - 2"r" + 1)`
Concept: undefined >> undefined
Find `sum_("r" = 1)^"n"((1 + 2 + 3 .... + "r")/"r")`
Concept: undefined >> undefined
Find `sum_("r" = 1)^"n" [(1^3 + 2^3 + .... + "r"^3)/("r"("r" + 1))]`
Concept: undefined >> undefined
Find the sum 5 × 7 + 9 × 11 + 13 × 15 + ... upto n terms
Concept: undefined >> undefined
Find the sum 22 + 42 + 62 + 82 + ... upto n terms
Concept: undefined >> undefined
Find (702 – 692) + (682 – 672) + (662 – 652) + ... + (22 – 12)
Concept: undefined >> undefined
Find the sum 1 × 3 × 5 + 3 × 5 × 7 + 5 × 7 × 9 + ... + (2n – 1) (2n + 1) (2n + 3)
Concept: undefined >> undefined
If `(1 xx 2 + 2 xx 3 + 3 xx 4 + 4 xx 5 + ... "upto n terms")/(1 + 2 + 3 + 4 + ... "upto n terms") = 100/3,` find n
Concept: undefined >> undefined
If S1, S2 and S3 are the sums of first n natural numbers, their squares and their cubes respectively then show that - 9S22 = S3 (1 + 8 S1)
Concept: undefined >> undefined
Answer the following:
Find 2 + 22 + 222 + 2222 + ... upto n terms
Concept: undefined >> undefined
Answer the following:
Find `sum_("r" = 1)^"n" (5"r"^2 + 4"r" - 3)`
Concept: undefined >> undefined
Answer the following:
Find `sum_("r" = 1)^"n" "r"("r" - 3)("r" - 2)`
Concept: undefined >> undefined
Answer the following:
Find `sum_("r" = 1)^"n" ((1^2 + 2^2 + 3^2 + ... + "r"^2)/(2"r" + 1))`
Concept: undefined >> undefined
