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Find the equation of the ellipse in the case:
eccentricity e = \[\frac{1}{2}\] and foci (± 2, 0)
Concept: undefined >> undefined
Find the equation of the ellipse in the case:
eccentricity e = \[\frac{2}{3}\] and length of latus rectum = 5
Concept: undefined >> undefined
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Find the equation of the ellipse in the case:
eccentricity e = \[\frac{1}{2}\] and semi-major axis = 4
Concept: undefined >> undefined
Find the equation of the ellipse in the case:
eccentricity e = \[\frac{1}{2}\] and major axis = 12
Concept: undefined >> undefined
Find the equation of the ellipse in the case:
The ellipse passes through (1, 4) and (−6, 1).
Concept: undefined >> undefined
Find the equation of the ellipse in the case:
Vertices (± 5, 0), foci (± 4, 0)
Concept: undefined >> undefined
Find the equation of the ellipse in the case:
Vertices (0, ± 13), foci (0, ± 5)
Concept: undefined >> undefined
If A = {1, 2, 3, 4}, B = {3, 4, 5, 6}, C = {5, 6, 7, 8} and D = {7, 8, 9, 10}; find
A ∪ C
Concept: undefined >> undefined
Find the intersection of pair of sets:
X = {1, 3, 5}, Y = {1, 2, 3}
Concept: undefined >> undefined
Find the intersection of pair of sets:
A = {a, e, i, o, u}, B = {a, b, c}
Concept: undefined >> undefined
Find the intersection of pair of sets:
A = {x : x is a natural number and multiple of 3}
B = {x : x is a natural number less than 6}
Concept: undefined >> undefined
Find the intersection of pair of sets:
A = {x : x is a natural number and 1 < x ≤ 6}
B = {x : x is a natural number and 6 < x < 10}
Concept: undefined >> undefined
Find the intersection of pair of sets:
A = {1, 2, 3}, B = Φ
Concept: undefined >> undefined
If A = {3, 5, 7, 9, 11}, B = {7, 9, 11, 13}, C = {11, 13, 15} and D = {15, 17}; find
A ∩ B
Concept: undefined >> undefined
If A = {x : x is a natural number}, B = {x : x is an even natural number} C = {x : x is an odd natural number} and D = {x : x is a prime number}, find:
A ∩ B
Concept: undefined >> undefined
Let A, B and C be the sets such that A ∪ B = A ∪ C and A ∩ B = A ∩ C. Show that B = C.
Concept: undefined >> undefined
Show that the following four conditions are equivalent:
- A ⊂ B
- A – B = Φ
- A ∪ B = B
- A ∩ B = A
Concept: undefined >> undefined
Using properties of sets show that A ∪ (A ∩ B) = A
Concept: undefined >> undefined
Show that A ∩ B = A ∩ C need not imply B = C.
Concept: undefined >> undefined
Let A and B be sets. If A ∩ X = B ∩ X = Φ and A ∪ X = B ∪ X for some set X, show that A = B.
(Hints A = A ∩ (A ∪ X), B = B ∩ (B ∪ X) and use distributive law)
Concept: undefined >> undefined
