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(English Medium) ICSE Class 9 - CISCE Question Bank Solutions for Mathematics

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Mathematics
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Solve for x: `4^(x-1) × (0.5)^(3 - 2x) = (1/8)^-x`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x :  (a3x + 5)2. (ax)4 = a8x + 12

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

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Solve for x: 

`(81)^(3/4) - (1/32)^(-2/5) + x(1/2)^(-1).2^0 = 27`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x:

`2^(3x  +  3) = 2^(3x  +  1) + 48`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve for x :  3(2x + 1) - 2x + 2 + 5 = 0

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If 4x + 3 = 112 + 8 × 4x, find the value of (18x)3x.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If 5x + 1 = 25x - 2, find the value of  3x - 3 × 23 - x.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If m ≠ n and (m + n)-1 (m-1 + n-1) = mxny, show that : x + y + 2 = 0

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If 5-P = 4-q = 20r, show that : `1/p + 1/q + 1/r = 0`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If ax = by = cz and b2 = ac, prove that: y = `[2xz]/[x + z]`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If ax = b, by = c and cz = a, prove that : xyz = 1.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Prove that : `((x^a)/(x^b))^( a + b - c ) (( x^b)/(x^c))^( b + c - a )((x^c)/(x^a))^( c + a - b)`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Prove that :
`[ x^(a(b - c))]/[x^b(a - c)] ÷ ((x^b)/(x^a))^c = 1`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Find the values of m and n if : 
`4^(2m) = ( root(3)(16))^(-6/n) = (sqrt8)^2`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve x and y if : ( √32 )x ÷ 2y + 1 = 1 and 8y - 164 - x/2 = 0

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Evaluate : `[(-2/3)^-2]^3 xx (1/3)^-4 xx 3^-1 xx 1/6`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Simplify : `[ 3 xx 9^( n + 1 ) - 9 xx 3^(2n)]/[3 xx 3^(2n + 3) - 9^(n + 1 )]`

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

Solve : 3x-1× 52y-3 = 225.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If `((a^-1b^2 )/(a^2b^-4))^7 ÷ (( a^3b^-5)/(a^-2b^3))^-5 = a^x . b^y` , find x + y.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined

If 3x + 1 = 9x - 3 , find the value of 21 + x.

[7] Indices [Exponents]
Chapter: [7] Indices [Exponents]
Concept: undefined >> undefined
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