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ISC (Commerce) इयत्ता १२ - CISCE Question Bank Solutions

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'कालिदास जहाँ एक तरफ अप्रतिम प्रतिभा के स्वामी हैं, तो वहीं दूसरी तरफ उनके स्वभाव में दुर्बलताओं को भी देखा गया है।` - इस कथन को ध्यान में रखते हुए कालिदास का चरित्र-चित्रण कीजिए।

[1] गद्य (Prose)
Chapter: [1] गद्य (Prose)
Concept: undefined >> undefined

Solve for x:
`tan^-1 [(x-1),(x-2)] + tan^-1 [(x+1),(x+2)] = x/4`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

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Evaluate: tan `[ 2 tan^-1  (1)/(2) – cot^-1 3]`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Solve for x:

5tan–1x + 3cot–1x = 2π

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of `tan^-1(x/y) + tan^-1((y - x)/(y + x))`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

The binary operation *: R x R → R is defined as a *b = 2a + b Find (2 * 3)*4

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

A relation R on (1, 2, 3) is given by R = {(1, 1), (2, 2), (1, 2), (3, 3), (2, 3)}. Then the relation R is ______.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let L be a set of all straight lines in a plane. The relation R on L defined as 'perpendicular to' is ______.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Statement 1: The intersection of two equivalence relations is always an equivalence relation.

Statement 2: The Union of two equivalence relations is always an equivalence relation.

Which one of the following is correct?

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If a relation R on the set {a, b, c} defined by R = {(b, b)}, then classify the relation.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Prove that:

`sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

If cos-1 x + cos -1 y + cos -1 z = π , prove that x2 + y2 + z2 + 2xyz = 1.

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

If y = `(x sin^-1 x)/sqrt(1 -x^2)`, prove that: `(1 - x^2)dy/dx = x + y/x`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Find the value of the expression in terms of x, with the help of a reference triangle

sin (cos–1(1 – x))

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

If `tan^-1 ((x - 1)/(x + 1)) + tan^-1 ((2x - 1)/(2x + 1)) = tan^-1 (23/36)` = then prove that 24x2 – 23x – 12 = 0

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

The value of cosec `[sin^-1((-1)/2)] - sec[cos^-1((-1)/2)]` is equal to ______.

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Solve for x: `sin^-1(x/2) + cos^-1x = π/6`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

If sin–1x + sin–1y + sin–1z = π, show that `x^2 - y^2 - z^2 + 2yzsqrt(1 - x^2) = 0`

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

Solve:

sin–1 (x) + sin–1 (1 – x) = cos–1 x

[2] Inverse Trigonometric Functions
Chapter: [2] Inverse Trigonometric Functions
Concept: undefined >> undefined

If the function `f(x) = sqrt(2x - 3)` is invertible then find its inverse. Hence prove that `(fof^(-1))(x) = x`

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined
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