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Science (English Medium) इयत्ता १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
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Find the equation of the normal at a point on the curve x2 = 4y which passes through the point (1, 2). Also find the equation of the corresponding tangent.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

The equation of tangent at (2, 3) on the curve y2 = ax3 + b is y = 4x – 5. Find the values of a and b.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

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 If x=a sin 2t(1+cos 2t) and y=b cos 2t(1cos 2t), find `dy/dx `

 
[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined
 
 

Evaluate : `∫_0^(π/2)(sin^2 x)/(sinx+cosx)dx`

 
 
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
 

Prove that the least perimeter of an isosceles triangle in which a circle of radius r can be inscribed is `6sqrt3` r.

 
[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

If x=α sin 2t (1 + cos 2t) and y=β cos 2t (1cos 2t), show that `dy/dx=β/αtan t`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined
 

Evaluate :`int_0^(pi/2)(2^(sinx))/(2^(sinx)+2^(cosx))dx`

 
[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Find the equation of tangents to the curve y= x3 + 2x – 4, which are perpendicular to line x + 14y + 3 = 0.

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

If x = a sin 2t (1 + cos2t) and y = b cos 2t (1 – cos 2t), find the values of  `dy/dx `at t = `pi/4`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x = a sin 2t (1 + cos 2t) and y = b cos 2t (1 – cos 2t) then find `dy/dx `

 

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Show that the equation of normal at any point t on the curve x = 3 cos t – cos3t and y = 3 sin t – sin3t is 4 (y cos3t – sin3t) = 3 sin 4t

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Show that the equation of normal at any point t on the curve x = 3 cos t – cos3t and y = 3 sin t – sin3t is 4 (y cos3t – sin3t) = 3 sin 4t

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Find the value of `dy/dx " at " theta =pi/4 if x=ae^theta (sintheta-costheta) and y=ae^theta(sintheta+cos theta)`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find the equations of the tangent and normal to the curve `x^2/a^2−y^2/b^2=1` at the point `(sqrt2a,b)` .

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

If x = cos t (3 – 2 cos2 t) and y = sin t (3 – 2 sin2 t), find the value of dx/dy at t =4/π.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 2at2, y = at4

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = a cos θ, y = b cos θ

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = sin t, y = cos 2t

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = 4t, y = `4/y`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If x and y are connected parametrically by the equations, without eliminating the parameter, find `bb(dy/dx)`.

x = cos θ – cos 2θ, y = sin θ – sin 2θ

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined
< prev  5521 to 5540 of 8306  next > 
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