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Arts (English Medium) इयत्ता १२ - CBSE Question Bank Solutions for Mathematics

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Mathematics
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Find the distance between the planes 2x - y +  2z = 5 and 5x - 2.5y + 5z = 20

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the shortest distance between the lines: 

`vecr = (hati+2hatj+hatk) + lambda(hati-hatj+hatk)` and `vecr = 2hati - hatj - hatk + mu(2hati + hatj + 2hatk)`

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

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Find the shortest distance between the lines.

`(x + 1)/7 = (y + 1)/(- 6) = (z + 1)/1` and `(x - 3)/1 = (y - 5)/(- 2) = (z - 7)/1`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the shortest distance between the lines whose vector equations are `vecr = (hati + 2hatj + 3hatk) + lambda(hati - 3hatj + 2hatk)` and `vecr = 4hati + 5hatj + 6hatk + mu(2hati + 3hatj + hatk)`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the shortest distance between the lines whose vector equations are `vecr = (1-t)hati + (t - 2)hatj + (3 -2t)hatk` and `vecr = (s+1)hati + (2s + 1)hatk`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the shortest distance between lines `vecr = 6hati + 2hatj + 2hatk + lambda(hati - 2hatj + 2hatk)` and `vecr =-4hati - hatk + mu(3hati - 2hatj - 2hatk)`.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

`y = tan^(-1) ((3x -x^3)/(1 - 3x^2)), - 1/sqrt3 < x < 1/sqrt3`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

y = `cos^(-1) ((1-x^2)/(1+x^2))`, 0 < x < 1

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

y = `sin^(-1) ((1-x^2)/(1+x^2))`, 0 < x < 1

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

y = `cos^(-1) ((2x)/(1+x^2))`, −1 < x < 1

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

y = `sin^(-1)(2xsqrt(1-x^2)), -1/sqrt2 < x < 1/sqrt2`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `bb(dy/dx)` in the following:

y = `sec^(-1) (1/(2x^2 - 1)), 0 < x < 1/sqrt2`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x:

`cot^(-1) [(sqrt(1+sinx) + sqrt(1-sinx))/(sqrt(1+sinx) - sqrt(1-sinx))], 0 < x < pi/2`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Differentiate the function with respect to x:

`(sin x - cos x)^((sin x - cos x)), pi/4 < x < (3pi)/4`

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find `dy/dx`, if y = `sin^-1 x + sin^-1 sqrt (1 - x^2)`, 0 < x < 1.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

If `xsqrt(1+y) + y  sqrt(1+x) = 0`, for, −1 < x < 1, prove that `dy/dx = -1/(1+ x)^2`.

[5] Continuity and Differentiability
Chapter: [5] Continuity and Differentiability
Concept: undefined >> undefined

Find the unit vector in the direction of the vector `veca = hati + hatj + 2hatk`.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Find the unit vector in the direction of vector `vec(PQ)`, where P and Q are the points (1, 2, 3) and (4, 5, 6), respectively.

[10] Vectors
Chapter: [10] Vectors
Concept: undefined >> undefined

Integrate the function `(3x^2)/(x^6 + 1)`

[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined

Integrate the function `1/sqrt(1+4x^2)`

[7] Integrals
Chapter: [7] Integrals
Concept: undefined >> undefined
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