English Medium इयत्ता १० - CBSE Question Bank Solutions

`1+((tan^2 theta) cot theta)/(cosec^2 theta) = tan theta`

`(tan^2theta)/((1+ tan^2 theta))+ cot^2 theta/((1+ cot^2 theta))=1`

`sin theta / ((1+costheta))+((1+costheta))/sin theta=2cosectheta` 

`tan theta /((1 - cot theta )) + cot theta /((1 - tan theta)) = (1+ sec theta cosec  theta)`

`cos^2 theta /((1 tan theta))+ sin ^3 theta/((sin theta - cos theta))=(1+sin theta cos theta)`

`costheta/((1-tan theta))+sin^2theta/((cos theta-sintheta))=(cos theta+ sin theta)`

`(1+tan^2theta)(1+cot^2 theta)=1/((sin^2 theta- sin^4theta))`

`tan theta/(1+ tan^2 theta)^2 + cottheta/(1+ cot^2 theta)^2 = sin theta cos theta`

`sin^6 theta + cos^6 theta =1 -3 sin^2 theta cos^2 theta`

`sin^2 theta + cos^4 theta = cos^2 theta + sin^4 theta`

cosec⁴θ − cosec²θ = cot⁴θ + cot²θ

`(1+ tan^2 theta)/(1+ tan^2 theta)= (cos^2 theta - sin^2 theta)`

`(1-tan^2 theta)/(cot^2-1) = tan^2 theta`

`(tan theta)/((sec theta -1))+(tan theta)/((sec theta +1)) = 2 sec theta`

`(cot ^theta)/((cosec theta+1)) + ((cosec theta + 1))/cot theta = 2 sec theta`

`cot theta/((cosec  theta + 1) )+ ((cosec  theta +1 ))/ cot theta = 2 sec theta `

`(sec theta -1 )/( sec theta +1) = ( sin ^2 theta)/( (1+ cos theta )^2)`

`(sectheta- tan theta)/(sec theta + tan theta) = ( cos ^2 theta)/( (1+ sin theta)^2)`

`sqrt((1+sin theta)/(1-sin theta)) = (sec theta + tan theta)`

`sqrt((1-cos theta)/(1+cos theta)) = (cosec  theta - cot  theta)`