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SSC (Marathi Semi-English) इयत्ता १० वी - Maharashtra State Board Important Questions for Geometry Mathematics 2

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Geometry Mathematics 2
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In the following figure RP : PK= 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).

Appears in 3 question papers
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

Out of the following, which is the Pythagorean triplet?

Appears in 3 question papers
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

In the given figure, m(arc NS) = 125°, m(arc EF) = 37°, find the measure ∠NMS.

Appears in 3 question papers
Chapter: [3] Circle
Concept: Touching Circles

Prove the following theorem:

Tangent segments drawn from an external point to the circle are congruent.

Appears in 3 question papers
Chapter: [3] Circle
Concept: Tangent Segment Theorem

∆ABC ~ ∆LMN. In ∆ABC, AB = 5.5 cm, BC = 6 cm, CA = 4.5 cm. Construct ∆ABC and ∆LMN such that `"BC"/"MN" = 5/4`.

Appears in 3 question papers
Chapter: [4] Geometric Constructions
Concept: Construction of Similar Triangle

Determine whether the points are collinear.

A(1, −3), B(2, −5), C(−4, 7)

Appears in 3 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Distance Formula

In the following figure seg AB ⊥ seg BC, seg DC ⊥ seg BC. If AB = 2 and DC = 3, find `(A(triangleABC))/(A(triangleDCB))`

Appears in 2 question papers
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In the given figure, AD is the bisector of the exterior ∠A of ∆ABC. Seg AD intersects the side BC produced in D. Prove that:

\[\frac{BD}{CD} = \frac{AB}{AC}\]
Appears in 2 question papers
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In the given figure, ∠MNP = 90°, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.

Appears in 2 question papers
Chapter: [2] Pythagoras Theorem
Concept: Theorem of Geometric Mean

Some question and their alternative answer are given.

In a right-angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?

Appears in 2 question papers
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Find the perimeter of a square if its diagonal is `10sqrt2` cm:

Appears in 2 question papers
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

In ΔPQR, seg PM is a median, PM = 9 and PQ2 + PR2  = 290. Find the length of QR. 

Appears in 2 question papers
Chapter: [2] Pythagoras Theorem
Concept: Apollonius Theorem

Find the side of a square whose diagonal is `10sqrt2` cm.

Appears in 2 question papers
Chapter: [2] Pythagoras Theorem
Concept: Pythagoras Theorem

Chord AB and chord CD of a circle with centre 0 are congruent. If m(arc AB) = 120°, then find the m(arc CD).

Appears in 2 question papers
Chapter: [3] Circle
Concept: Property of Sum of Measures of Arcs

Write down the equation of a line whose slope is 3/2 and which passes through point P, where P divides the line segment AB joining A(-2, 6) and B(3, -4) in the ratio 2 : 3.

Appears in 2 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Division of a Line Segment

ΔRST ~ ΔUAY, In ΔRST, RS = 6 cm, ∠S = 50°, ST = 7.5 cm. The corresponding sides of ΔRST and ΔUAY are in the ratio 5 : 4. Construct ΔUAY.

Appears in 2 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Division of a Line Segment

Construct the circumcircle and incircle of an equilateral ∆XYZ with side 6.5 cm and centre O. Find the ratio of the radii of incircle and circumcircle.

Appears in 2 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Division of a Line Segment

∆PQR ~ ∆LTR. In ∆PQR, PQ = 4.2 cm, QR = 5.4 cm, PR = 4.8 cm. Construct ∆PQR and ∆LTR, such that `"PQ"/"LT" = 3/4`.

Appears in 2 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Division of a Line Segment

Find distance between point Q(3, –7) and point R(3, 3)

Solution: Suppose Q(x1, y1) and point R(x2, y2)

x1 = 3, y1 = –7 and x2 = 3, y2 = 3

Using distance formula,

d(Q, R) = `sqrt(square)`

∴ d(Q, R) = `sqrt(square - 100)`

∴ d(Q, R) =  `sqrt(square)`

∴ d(Q, R) = `square`

Appears in 2 question papers
Chapter: [5] Co-ordinate Geometry
Concept: Distance Formula

Prove that sin6θ + cos6θ = 1 – 3 sin2θ. cos2θ.

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)
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