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Commerce (English Medium) इयत्ता १२ - CBSE Important Questions for Mathematics

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Find the distance of the point P(3, 4, 4) from the point, where the line joining the points A(3, –4, –5) and B(2, –3, 1) intersects the plane 2x + y + z = 7.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Plane Passing Through the Intersection of Two Given Planes

Find the equation of the plane that contains the point (1, –1, 2) and is perpendicular to both the planes 2x + 3y – 2z = 5 and x + 2y – 3z = 8. Hence, find the distance of point P (–2, 5, 5) from the plane obtained

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

Find the distance of the point P (–1, –5, –10) from the point of intersection of the line joining the points A (2, –1, 2) and B (5, 3, 4) with the plane x – y + z = 5.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

If a plane passes through the point (1, 1, 1) and is perpendicular to the line \[\frac{x - 1}{3} = \frac{y - 1}{0} = \frac{z - 1}{4}\] then its perpendicular distance from the origin is ______.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

If a plane passes through the point (1, 1, 1) and is perpendicular to the line \[\frac{x - 1}{3} = \frac{y - 1}{0} = \frac{z - 1}{4}\] then its perpendicular distance from the origin is ______.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the direction cosines of the line joining the points P(4,3,-5) and Q(-2,1,-8) . 

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Direction Cosines and Direction Ratios of a Line

Find the value of p for which the following lines are perpendicular : 

`(1-x)/3 = (2y-14)/(2p) = (z-3)/2 ; (1-x)/(3p) = (y-5)/1 = (6-z)/5`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the value of  λ for which the following lines are perpendicular to each other: 

`(x - 5)/(5 lambda + 2 ) = ( 2 - y )/5 = (1 - z ) /-1 ; x /1 = ( y + 1/2)/(2 lambda ) = ( z -1 ) / 3`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the vector and cartesian equations of the plane passing throuh the points (2,5,- 3), (-2, - 3,5) and (5,3,-3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (–1, –3, –1).

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the equation of the plane passing through the intersection of the planes `vec(r) .(hat(i) + hat(j) + hat(k)) = 1"and" vec(r) . (2 hat(i) + 3hat(j) - hat(k)) +4 = 0 `and parallel to x-axis. Hence, find the distance of the plane from x-axis.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the value of λ for which the following lines are perpendicular to each other `("x"-5)/(5λ+2) = (2 -"y")/(5) = (1 -"z")/(-1); ("x")/(1) = ("y"+1/2)/(2λ) = ("z" -1)/(3)`

hence, find whether the lines intersect or not

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Equation of a Plane Perpendicular to a Given Vector and Passing Through a Given Point

Find the equation of the plane passing through the intersection of the planes `vecr . (hati + hatj + hatk)` and `vecr.(2hati + 3hatj - hatk) + 4 = 0` and parallel to the x-axis. Hence, find the distance of the plane from the x-axis.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Plane Passing Through the Intersection of Two Given Planes

Find the vector and cartesian equation of the plane passing through the point (2, 5, - 3), (-2, -3, 5) and (5, 3, -3). Also, find the point of intersection of this plane with the line passing through points (3, 1, 5) and (-1, -3, -1).

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Write the coordinates of the point which is the reflection of the point (α, β,  γ) in the XZ-plane.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Write the coordinates of the point which is the reflection of the point (α, β,  γ) in the XZ-plane.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Show that the lines `("x"-1)/(3) = ("y"-1)/(-1) = ("z"+1)/(0) = λ and  ("x"-4)/(2) = ("y")/(0) = ("z"+1)/(3)` intersect. Find their point of intersection. 

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Plane >> Plane Passing Through the Intersection of Two Given Planes

Find the coordinates of the foot of perpendicular and perpendicular distance from the point P(4,3,2) to the plane x + 2y + 3z = 2. Also find the image of P in the plane.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Three - Dimensional Geometry Examples and Solutions

Find the shortest distance between the following lines:

`vecr = (hati + hatj - hatk) + s(2hati + hatj + hatk)`

`vecr = (hati + hatj - 2hatk) + t(4hati + 2hatj + 2hatk)`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Shortest Distance Between Two Lines

Find the vector and the cartesian equations of the plane containing the point `hati + 2hatj - hatk` and parallel to the lines `vecr = (hati + 2hatj + 2hatk) + s(2hati - 3hatj + 2hatk)` and `vecr = (3hati + hatj - 2hatk) + t(hati - 3hatj + hatk)`

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the foot of the perpendicular from the point (1, 2, 0) upon the plane x – 3y + 2z = 9. Hence, find the distance of the point (1, 2, 0) from the given plane.

Appears in 1 question paper
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane
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