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Xn Loga X - Mathematics

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प्रश्न

xn loga 

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उत्तर

\[\text{ Let } u = x^n ; v = \log_a x = \frac{\log x}{\log a}\]
\[\text{ Then }, u' = n x^{n - 1} ; v' = \frac{1}{x \log a}\]
\[\text{ Using the product rule }:\]
\[\frac{d}{dx}\left( uv \right) = uv' + vu'\]
\[\frac{d}{dx}\left( x^n \log_a x \right) = x^n . \frac{1}{x \log a} + \log_a x \left( n x^{n - 1} \right)\]
\[ = x^{n - 1} \frac{1}{\log a} + \log_a x \left( n x^{n - 1} \right)\]
\[ = x^{n - 1} \left( \frac{1}{\log a} + n \log_a x \right)\]

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पाठ 30: Derivatives - Exercise 30.4 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 30 Derivatives
Exercise 30.4 | Q 5 | पृष्ठ ३९

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