Advertisements
Advertisements
प्रश्न
x3 − 3x2 − 9x − 5
Advertisements
उत्तर
Let `f(x) = x^3 - 3x^2 - 9x -5 ` be the given polynomial.
Now, putting x = 1,we get
`f(-1) = (-1)^3 -3(-1)^ -9(-1) - 5`
`=-1 -3 +9 -5 = -9 +9 = 0`
Therefore, (x + 1)is a factor of polynomial f(x).
Now,
`f(x) = x^2 (x+1) -4x(x+1) -5(x +1)`
` = (x+1){x^2 -4x -5}`
` =(x+1){x^2 - 5x + x -5}`
` = (x+1)(x+1)( x-5)`
Hence (x+1) , (x+1) and (x - 5) are the factors of polynomial f(x) .
APPEARS IN
संबंधित प्रश्न
Identify constant, linear, quadratic and cubic polynomials from the following polynomials:
`f(x)=0`
Identify constant, linear, quadratic and cubic polynomials from the following polynomials
`p(x)=2x^2-x+4`
f(x) = 3x3 + x2 − 20x +12, g(x) = 3x − 2
Find the values of a and b, if x2 − 4 is a factor of ax4 + 2x3 − 3x2 + bx − 4.
x3 − 23x2 + 142x − 120
x4 + 10x3 + 35x2 + 50x + 24
If x − a is a factor of x3 −3x2a + 2a2x + b, then the value of b is
If x + 2 is a factor of x2 + mx + 14, then m =
If x − 3 is a factor of x2 − ax − 15, then a =
Factorise:
3x3 – x2 – 3x + 1
