Question

`x^2-(1+sqrt2)x+sqrt2=0` 

 

Answer 1

`x^2-(1+sqrt2)x+sqrt2=0` 

⇒` x^2-x-sqrt2x+sqrt2=0`  

⇒`x(x-1)-sqrt2(x-1)=0` 

⇒` (x-sqrt2)(x-1)=0` 

⇒`x=sqrt2=0   or  x-1=0 ` 

⇒`x=sqrt2 or x=1` 

Hence, the roots of the equation are `sqrt2` and 1