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प्रश्न
Write two integers which are smaller than –5 but their difference is –5.
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उत्तर
For two integers, which are smaller than –5 but their difference is –5.
Let first integer = –11 and second integer = (–6) ...[∵ –11 < (–5) and –6 < (–5)]
Difference = –11 – (–6) = –11 + 6 = (–5)
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संबंधित प्रश्न
Use the sign of >, < or = in the box to make the statements true.
– 231 + 79 + 51 
–399 + 159 + 81
Subtract the numbers in the top row from the numbers in the first column and write the proper number in each empty box.
| – | 6 | 9 | –4 | –5 | 0 | +7 | –8 | –3 |
| 3 | 3 – 6 = –3 | |||||||
| 8 | 8 − (−5) = 13 | |||||||
| –3 | ||||||||
| –2 |
Add: -3596 and -1089
Subtract: −135 from −250
Simplify: (−9) × 6 + (−9) × 4
Write all integers from −5 to 5.
The predecessor of the integer –1 is ______.
Every positive integer is larger than every negative integer.
An atom changes to a charged particle called ion if it loses or gains electrons. The charge on an ion is the charge on electrons plus charge on protons. Now, write the missing information in the table given below:
| Name of Ion | Proton Charge | Electron Charge | Ion Charge |
| Hydroxide ion | +9 | – | –1 |
| Sodium ion | +11 | – | +1 |
| Aluminium ion | +13 | –10 | – |
| Oxide ion | +8 | –10 | – |
Write the integers between the given pairs (write them in increasing order)
–8 and –15
