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Write the formulae for the following compound: Mercury(II) chloride - Chemistry

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प्रश्न

Write the formulae for the following compound:

Mercury(II) chloride

एक शब्द/वाक्यांश उत्तर
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उत्तर

Mercury (II) chloride: HgCl2

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Classical Idea of Redox Reactions - Oxidation and Reduction Reactions
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?

संबंधित प्रश्‍न

EΘ values of some redox couples are given below. On the basis of these values.

EΘ values: \[\ce{Br2 /Br- = + 1.90; Ag+ / Ag(s) = + 0.80}\];

\[\ce{Cu^{2+} / Cu(s) = + 0.34; I2(s) / I- = 0.54}\]


According to the classical concept, involves one of the following?  


(A) \[\ce{HOCl + H2O2 -> H3O^+ + Cl^- + O2}\]

(B) \[\ce{I2 + H2O2 + 2OH^- -> 2I^- + 2H2O + O2}\]

Choose the correct option.


Given below are two statements:

Statement I: The E° value for \[\ce{\frac{Ce^{4+}}{Ce^{3+}}}\] is +1.74 V.

Statement II: Ce is more stable in Ce4+ state than Ce3+ state.

In the light of the above statements, choose the correct answer from the options given below:


\[\ce{2MnO^-4 + {b}C2O^{2-}4 + {c}H^+ -> {x}Mn^{2+} + {y}CO2 + {z}H2O}\]

If the above equation is balanced with integer coefficients, the value of c is ______. (Round off to the Nearest Integer).


Given, that `"E"_("O"_2//"H"_2"O")^circ` = + 1.23 V;

`"E"_("S"_2"O"_8^{2-}//"SO"_4^(2-))` = 2.05 V;

`"E"_("Br"_2//"Br")^circ` = 1.09 V;

`"E"_("Au"^{2+}//"Au")^circ` = + 1.4 V

The strongest oxidizing agent is:


In which of the following reaction, H2O2 is behaving as a reducing agent:


Ge (II) compounds are powerful reducing agents, whereas Pb (IV) compounds are strong oxidants. It can be due to ______.


Oxidizing agent (A) used is ______.


The compound that cannot act both as oxidizing and reducing agent is ______.


Copper becomes green when exposed to moist air for a long period. This is due to ______


Which one of the following cannot function as an oxidizing agent?


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