Advertisements
Advertisements
प्रश्न
Write the coefficient of x2 in the following:
`pi/6 x + x^2 - 1`
Advertisements
उत्तर
`pi/6 x + x^2 - 1 = pi/6 x + (1) x^2 - 1`
The coefficient of x2 in the polynomial `π/6 x + x^2 - 1` = 1.
APPEARS IN
संबंधित प्रश्न
Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer:
`y^2 +2sqrt3`
Which of the following expressions are polynomials in one variable and which are not? State reasons for your answer:
`x^12+y^3+t^50`
Write the coefficient of x2 in the following:-
`sqrt2x-1`
Which of the following expression are polynomial? Justify your answer:
8
Which of the following expression are polynomial? Justify your answer:
`1 - sqrt(5)x`
Find the value of the polynomial 3x3 – 4x2 + 7x – 5, when x = 3 and also when x = –3.
If p(x) = x2 – 4x + 3, then evaluate : `p(2) - p(–1) + p(1/2)`
Following expression is polynomial in one variable or not? State reason for your answer.
`y^2+sqrt2`
Following expression is polynomial in one variable or not? State reason for your answer.
x10 + y3 + t50
The degree of 12 − p6 + 3p2 is:
