Question

Write down the time period of simple pendulum.

Answer 1

The angular frequency of this oscillator (natural frequency of this system) is

ω² = `"g"/"l"`

∴ ω = `sqrt("g"/"l")` in rad s⁻¹

The frequency of oscillations is

f = `1/(2π) sqrt("g"/"l")` in Hz

and time period of oscillations is

T = `2π sqrt("g"/"l")` in second