Question

Write a C++ program to input ‘n’ elements in an one dimensional array and input one another number and check whether this number is present in the array or not.

Answer 1

#include <iostream>
using namespace std;

int main()
{
    int n;

    cout << "Enter number of elements: ";
    cin >> n;

    int arr[100];   // assuming maximum size 100

    cout << "Enter " << n << " elements: ";
    for(int i = 0; i < n; i++)
    {
        cin >> arr[i];
    }

    int num;
    cout << "Enter number to search: ";
    cin >> num;

    bool found = false;

    for(int i = 0; i < n; i++)
    {
        if(arr[i] == num)
        {
            found = true;
            break;
        }
    }

    if(found)
        cout << "Number is present in the array.";
    else
        cout << "Number is not present in the array.";

    return 0;
}

Explanation:

• First, we input n elements into a one-dimensional array.
• Then, we input another number to search.
• Using a loop, we compare each element with the given number.
• If a match is found, we print that the number is present; otherwise, it is not present.