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प्रश्न
Without using trigonometric tables, evaluate:
`sec 11^circ/("cosec" 79^circ)`
मूल्यांकन
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उत्तर
`sec 11^circ/("cosec" 79^circ)`
= `sec (90^circ - 79^circ)/("cosec" 79^circ)`
= `("cosec" 79^circ)/("cosec" 79^circ)` [`because sec (90 - theta) = "cosec" theta`]
= 1
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 12: Trigonometric Ratios of Some Complemantary Angles - EXERCISE 12 [पृष्ठ ५९०]
