Question

Without using trigonometric tables, evaluate:

`(cos 37^circ)/(sin 53^circ)`

Answer 1

Given: `(cos 37^circ)/(sin 53^circ)`

53° = 90° – 37°

So, sin 53° = sin (90° – 37°) = cos 37°   ...(using the complementary-angle identity sin (90° – θ) = cos θ).

Therefore, `(cos 37^circ)/(sin 53^circ) = (cos 37^circ)/(cos 37^circ)`

= 1