Question

Without actually calculating the cubes, find the value of:

(–32)³ + (15)³ + (17)³

Answer 1

(–32)³ + (15)³ + (17)³

Here, let a = –32, b = 15, c = 17

Let’s check if a + b + c = 0

–32 + 15 + 17 = 0

Using the identity:

a³ + b³ + c³ = 3abc

= 3 × (−32) × 15 × 17

= (−96) × 255

= −24,480