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प्रश्न
Why is \[x=0\] a critical point for \[f(x)=12x^{\frac{4}{3}}-6x^{\frac{1}{3}}\]?
पर्याय
\[f'(0)=1\].
\[f(0)\] is not defined.
\[f'(x)\] is not defined at \[x=0\].
\[f(0)=18\].
MCQ
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उत्तर
The derivative contains \[x^{\frac{2}{3}}\] in its denominator. Therefore, \[f'(x)\] is not defined at \[x=0\], making it a critical point.
shaalaa.com
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