Advertisements
Advertisements
प्रश्न
While factorizing a given polynomial using the remainder and factor theorem, a student finds that (2x + 1) is a factor of 2x3 + 7x2 + 2x – 3.
- Is the student’s solution correct in stating that (2x + 1) is a factor of the given polynomial?
- Give a valid reason for your answer.
Also, factorize the given polynomial completely.
Advertisements
उत्तर
f(x) = 2x3 + 7x2 + 2x – 3
`f(-1/2) = 2(-1/2)^3 + 7(-1/2)^2 + 2(-1/2) - 3 ≠ 0`
∴ (2x + 1) is not a factor of f(x).
`f(1/2) = 2(1/2)^3 + 7(1/2)^2 + 2(1/2) - 3 = 0`
∴ (2x – 1) is a factor of f(x)
x2 + 4x + 3
`2x - 1")"overline(2x^3 + 7x^2 + 2x - 3)`
2x3 – x2
8x2 + 2x
8x2 – 4x
6x – 3
6x – 3
xx
f(x) = (2x – 1)(x2 + 4x + 3)
f(x) = (2x – 1)(x + 3)(x + 1)
संबंधित प्रश्न
Find the number that must be subtracted from the polynomial 3y3 + y2 – 22y + 15, so that the resulting polynomial is completely divisible by y + 3.
Show that (x – 1) is a factor of x3 – 7x2 + 14x – 8. Hence, completely factorise the given expression.
If (x + 1) and (x – 2) are factors of x3 + (a + 1)x2 – (b – 2)x – 6, find the values of a and b. And then, factorise the given expression completely.
Factorise x3 + 6x2 + 11x + 6 completely using factor theorem.
Using the factor theorem, show that (x - 2) is a factor of `x^3 + x^2 -4x -4 .`
Hence factorise the polynomial completely.
In the following two polynomials, find the value of ‘a’ if x – a is a factor of each of the two:
x5 - a2x3 + 2x + a + 1.
If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x5 - 3x4 - ax3 + 3ax2 + 2ax + 4.
Prove that (5x + 4) is a factor of 5x3 + 4x2 – 5x – 4. Hence factorize the given polynomial completely.
If (x – a) is a factor of x3 – ax2 + x + 5; the value of a is ______.
(x – 2) is a factor of ______.
