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प्रश्न
Electron affinities of two elements A and B are given below:
A = 3.79 electron volts
B = 3.56 electron volts
Which of them will ionize more easily and why?
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उत्तर
Out of A and B, A will ionize more easily to form a negative anion because of the high value of electron affinity, energy released during addition of electron will be high hence the resulting anion formed will be more stable than the corresponding atom.
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संबंधित प्रश्न
Represent ionisation potential in the form of an equation. In which unit it is measured?
Name the elements with highest and lowest ionization energies in the first three periods.
Name the periodic property which relates to the amount of energy required to remove an electron from an isolated gaseous atom.
Give reason for the following:
Ionisation potential of the element increases across a period.
Which element from the following has the highest ionization energy?
Explain your choice.
P, Na, CI
Li, K, Na, H (In the decreasing order of their ionization potential)
A, B, C are three elements in which B is an inert gas other than helium.With this information complete the following table.
| Element | Atomic number | No. of electrons in the valence shell | Group to which the element belongs |
| A | Z - 1 | ||
| B | Z | ||
| C | Z + 1 |
Also, explain the following : Ionization energy of element C is less than that of element A.
State whether the ionization potential increases or decreases on going down a group.
which element has the highest ionisation potential.
Fill in the blank by selecting the correct word from the option.
If an element has a low ionization energy then it is likely to be ________
