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प्रश्न
Electron affinities of two elements A and B are given below:
A = 3.79 electron volts
B = 3.56 electron volts
Which of them will ionize more easily and why?
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उत्तर
Out of A and B, A will ionize more easily to form a negative anion because of the high value of electron affinity, energy released during addition of electron will be high hence the resulting anion formed will be more stable than the corresponding atom.
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संबंधित प्रश्न
Rewrite the following sentences by using the correct symbol > (greater than) or < (less than) in the blanks given
The ionization potential of potassium is _________________ that of sodium.
Which element from the following has the highest ionization energy?
Explain your choice.
P, Na, CI
Which element from the following has the highest ionization energy?
Explain your choice.
F, O, Ne
Choose the correct answer.
An element with highest ionization potential
(i) Calesium
(ii) Fluorine
(iii) Helium
(iv) Neon
In a group, a particular element has the lowest ionization potential; does it ionize most easily or least easily? Explain with example.
Rewrite the following sentence by using the correct > (greater than) or < (less than) in the blank given
The ionization potential of potassium is _______ that of sodium.
Arrange the following as per the instruction given in the bracket:
Potassium, Lithium, Sodium (increasing order of ionization potential).
Arrange the following as per instruction given in the bracket.
Na, Mg, Cl, S, Si (increasing ionisation potential)
Give reason:
Ionisation potential of the element increases across a period from left to right.
This question refers to the elements of the Periodic Table with atomic numbers from 3 to 18. Some of the elements are shown by letters, but the letters are not the usual symbols of the elements.
| 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| A | B | C | D | E | F | G | H |
| 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 |
| I | J | K | L | M | N | O | P |
Which of these have least Ionisation Energy?
