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प्रश्न
Which term of the progression `10, 9 1/3, 8 2/3,...` is the first negative term?
बेरीज
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उत्तर
Given:
`10, 9 1/3, 8 2/3,...`
First, write terms in improper fractions:
`10 = 30/3, 9 1/3 = 28/3, 8 2/3 = 26/3`
First term a = `30/3 = 10`
d = `28/3 - 30/3`
= `-2/3`
Tn = a + (n − 1)d
`T_n = 10 + (n − 1)(-2/3)`
The first negative term occurs when Tn < 0
`10 - 2/3(n - 1) < 0`
Multiply both sides by 3:
30 − 2(n − 1) < 0
30 − 2n + 2 < 0
32 − 2n < 0
2n > 32
⇒ n >16
The smallest whole number greater than 16 is 17.
The 17th term is the first negative term of the progression.
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