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प्रश्न
Which set can be the universal set?
P is the set of all residents in Pune.
M is the set of all residents in Madhya Pradesh.
I is the set of all residents in Indore.
B is the set of all residents in India.
H is the set of all residents in Maharashtra.
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उत्तर
The universal set is the set that contains all the other sets under consideration.
Here:
- P = Residents in Pune
- I = Residents in Indore
- H = Residents in Maharashtra
- M = Residents in Madhya Pradesh
- B = Residents in India
Since all residents of Pune, Maharashtra, Indore, and Madhya Pradesh are residents of India, set B contains all the other sets.
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संबंधित प्रश्न
Which set of numbers could be the universal set for the set given below?
A = set of multiples of 5.
B = set of multiples of 7.
C = set of multiples of 12.
Which set of numbers could be the universal set for the set given below?
P = set of integers which are multiples of 4.
T = set of all even square numbers.
Given the universal set = {-7,-3, -1, 0, 5, 6, 8, 9}, find: A = {x : x < 2}
Given the universal set = {x : x ∈ N and x < 20}, find:
B = {y : y = 2n + 3, n ∈ N}
Given the universal set = {x : x ∈ N and x < 20}, find:
C = {x : x is divisible by 4}
Given, universal set = {x : x ∈ N, 10 ≤ x ≤ 35}.
A = {x ∈ N : x ≤ 16} Find: A'
Given universal set = {x ∈ Z : -6 < x ≤6}.
N = {n : n is non-negative number}
Find: N'
Given universal set = {x ∈ Z : -6 < x ≤ 6}. P = {x : x is a non-positive number}. Find: P'
Given A = {x : x ∈ N and 3 < x ~ 6} and 8 = {x : x ∈ W and x < 4}. Find: A ∩ B.
For the universal set {4, 5, 6, 7, 8, 9, 10, 11,12,13} ; find the subset of C = {prime numbers}.
Also, find a complement of C.
If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find: A∪B
If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find: A∩B
If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find: A - B
If A = {4, 5, 6, 7, 8} and B = {6, 8, 10, 12}, find: B - A
If A = {3, 5, 7, 9, 11} and B = {4, 7, 10}, find: (A – B) and n(A – B)
If P = {x : x is a factor of 12} and Q = {x: x is a factor of 16}, find : Q – P and n(Q – P).
