मराठी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Which of the following options represents the correct bond order?

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प्रश्न

Which of the following options represents the correct bond order?

पर्याय

  • \[\ce{O^{-}2 > O2 > O^{+}2}\]

  • \[\ce{O^{-}2 < O2 < O^{+}2}\]

  • \[\ce{O^{-}2 > O2 < O^{+}2}\]

  • \[\ce{O^{-}2 < O2 > O^{+}2}\]

MCQ
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उत्तर

\[\ce{O^{-}2 < O2 < O^{+}2}\]

Explanation:

The electronic configurations and the bond orders of the given species are given below:

Bond order of \[\ce{O^{-}2}\]:

Electronic configuration:

`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2 (π2p_x^2 = 2p_y^2)(π^∗2p_x^1 = π^∗2p_y^1)`

Bond order = `1/2 (N_b - N_a)`

BO = `1/2(10 - 7) = 3/2 = 1.5`

Bond order of \[\ce{O^{+}2}\]:

Electronic configuration:

`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2 (π2p_x^2 = 2p_y^2)(π^∗2p_x^1 = π^∗2p_y^0)`

BO = `1/2(10 - 5) = 5/2 = 2.5`

Bond order of  \[\ce{O2}\]:

Electronic configuration:

`σ1s^2, σ^∗1s^2, σ2s^2, σ^∗2s^2, σ2p_z^2 (π2p_x^2 = 2p_y^2)(π^∗2p_x^1 = π^∗2p_y^1)`

BO = `(10 - 6)/2 = 4/2 = 2`

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पाठ 4: Chemical Bonding and Molecular Structure - Multiple Choice Questions (Type - I) [पृष्ठ ४२]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 4 Chemical Bonding and Molecular Structure
Multiple Choice Questions (Type - I) | Q 20 | पृष्ठ ४२
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