मराठी

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds? - Chemistry (Theory)

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प्रश्न

Which of the following is the correct order of increasing field strength of ligands to form coordination compounds?

पर्याय

  • \[\ce{SCN^- < F^- < C_2O^{2-}_4 < CN^-}\]

  • \[\ce{SCN^- < F^-  < CN^- < C_2O^{2-}_4}\]

  • \[\ce{F^- < SCN^- < C_2O^{2-}_4 < CN^-}\]

  • \[\ce{CN^- < C_2O^{2-}_4 < SCN^- < F^- }\]

MCQ
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उत्तर

\[\ce{SCN^- < F^- < C_2O^{2-}_4 < CN^-}\]

Explanation:

The ligands can be ranked based on their field strength, which refers to how strongly they affect the splitting of the metal’s d-orbitals in a coordination complex. The field strength of ligands is largely determined by their ability to donate electrons and interact with the metal ion. Stronger field ligands create a larger splitting of d-orbitals (larger Δ), which typically leads to a low-spin complex.

Order of Field Strength:

  • SCN (thiocyanate): This is a weak field ligand.
  • F (fluoride): Slightly stronger than SCN but still a weak field ligand.
  • \[\ce{C_2O^{2-}_4}\] (oxalate): A moderately strong field ligand, stronger than F.
  • CN (cyanide): A very strong field ligand, capable of causing the largest splitting of d-orbitals.

Thus, the correct order is:

\[\ce{SCN^- < F^- < C_2O^{2-}_4 < CN^-}\]

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पाठ 9: Coordination Compounds - OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS [पृष्ठ ५५२]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
पाठ 9 Coordination Compounds
OBJECTIVE (MULTIPLE CHOICE) TYPE QUESTIONS | Q 78. | पृष्ठ ५५२
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