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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान इयत्ता ११

Which of the following arrangements represent increasing oxidation number of the central atom?

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प्रश्न

Which of the following arrangements represent increasing oxidation number of the central atom?

पर्याय

  • \[\ce{CrO^{-}2, ClO^{-}3, CrO^{2-}4, MnO^{-}4}\]

  • \[\ce{ClO^{-}3, CrO^{2-}4, MnO^{-}4, CrO^{-}2}\]

  • \[\ce{CrO^{-}2, ClO^{-}3, MnO^{-}4, CrO^{2-}4}\]

  • \[\ce{CrO^{2-}4, MnO^{-}4, CrO^{-}2, ClO^{-}3}\]

MCQ
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उत्तर

\[\ce{CrO^{-}2, ClO^{-}3, CrO^{2-}4, MnO^{-}4}\]

Explanation:

Let the oxidation number of central atom be 'y'.

Oxidation number of \[\ce{O}\] = −2

\[\ce{CrO^{-}2}\]: y + 2 × (−2) = −1

y − 4 = −1 or y = +3

\[\ce{CrO^{2-}4}\]: y + 4 × (−2) = −2

y − 8 = −2 or y = +6

\[\ce{ClO^{-}3}\]: y + 3 × (−2) = −1

y − 6 = −1 or y = +5

\[\ce{MnO^{-}4}\]: y + 4 × (−2) = −1

y − 8 = −1 or y = +7

Increasing order of oxidation number of the central atom is:

\[\ce{CrO^{-}2 < ClO^{-}3 < CrO^{2-}4 < MNO^{-}4}\]

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पाठ 8: Redox Reactions - Multiple Choice Questions (Type - I) [पृष्ठ १०५]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 11
पाठ 8 Redox Reactions
Multiple Choice Questions (Type - I) | Q 8 | पृष्ठ १०५
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