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प्रश्न
Which expression gives the electric field due to an infinite line charge?
पर्याय
\[E = \frac{\lambda}{4\pi\varepsilon_0 r^2}\]
\[E = \frac{\lambda r}{2\pi\varepsilon_0}\]
\[E = \frac{\lambda}{2\pi\varepsilon_0 r}\]
\[E = \frac{\sigma}{2\varepsilon_0}\]
MCQ
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उत्तर
Using the cylindrical Gaussian surface gives \[E \cdot 2\pi r l = \lambda l/\varepsilon_0\]. Cancelling \[l\] yields \[E = \lambda/(2\pi\varepsilon_0 r)\].
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