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प्रश्न
When the diameter of a wire is doubled, its resistance becomes ______.
पर्याय
double
four times
one-half
one-fourth
MCQ
रिकाम्या जागा भरा
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उत्तर
When the diameter of a wire is doubled, its resistance becomes one-fourth.
Explanation:
We know that,
R = `(rho L)/A`
Area (A) ∝ d2
If the diameter is doubled, the new diameter d' = 2d.
Then the new area A' becomes:
A' = π(r')2
A' = `pi((d')/2)^2`
A' = πd2
A' = 4A
Since resistance R is inversely proportional to area, we can express the new resistance R' as:
R' = `(rho L)/(A')`
R' = `(rho L)/(4 A)`
R' = `R/4`
∴ The resistance becomes one-fourth of its original value, so the correct answer is (d) one-fourth.
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