Question

When current flowing through a solenoid decreases from 15 A to 0 in 0.2 s, an emf of 30 V is induced in it. Calculate the coefficient of self-inductance of the solenoid.

Answer 1

Given: dI = (15 − 0) = 15 A

e = 30 V

dt = 0.2 s

Coefficient of self-inductance,

L = `e/(dI//dt)`

= `30/(15//0.2)`

= `30/15 xx 0.2 H`

= 0.2 × 0.2 H

= 0.4 H