Advertisements
Advertisements
प्रश्न
What number should be subtracted from 2x3 – 5x2 + 5x so that the resulting polynomial has 2x – 3 as a factor?
Advertisements
उत्तर
Let the number to be subtracted be k and the resulting polynomial be f(x), then
f(x) = 2x3 – 5x2 + 5x – k
Since, 2x – 3 is a factor of f(x),
Now, converting 2x – 3 to factor theorem
`f(3/2)` = 0
⇒ 2x3 – 5x2 + 5x – k = 0
⇒ `2(3/2)^3 - 5(3/2)^2 +5(3/2) -k` = 0
⇒ `2 xx (27)/(8) - 5 xx (9)/(4) + 5 xx (3)/(2) - k` = 0
⇒ `(27)/(4) - (45)/(4) + (15)/(2) - k` = 0
⇒ 27 – 45 + 30 – 4k = 0
⇒ –4k + 12 = 0
⇒ k = `(-12)/(-4)`
⇒ k = 3.
APPEARS IN
संबंधित प्रश्न
Find the value of ‘a’, if (x – a) is a factor of x3 – ax2 + x + 2.
Using the factor Theorem, show that:
2x + 7 is a factor 2x3 + 5x2 − 11x – 14. Hence, factorise the given expression completely.
If x - 2 and `x - 1/2` both are the factors of the polynomial nx2 − 5x + m, then show that m = n = 2
Prove that (x - y) is a factor of yz( y2 - z2) + zx( z2 - x2) + xy ( x2 - y2)
Prove that (x-3) is a factor of x3 - x2 - 9x +9 and hence factorize it completely.
Show that (x - 1) is a factor of x3 - 7x2 + 14x - 8. Hence, completely factorise the above expression.
In the following problems use the factor theorem to find if g(x) is a factor of p(x):
p(x) = x3 - 3x2 + 4x - 4 and g(x) = x - 2
Using the Remainder and Factor Theorem, factorise the following polynomial: x3 + 10x2 – 37x + 26.
Find the value of ‘K’ for which x = 3 is a solution of the quadratic equation, (K + 2)x2 – Kx + 6 = 0. Also, find the other root of the equation.
If both (x − 2) and `(x - 1/2)` is the factors of ax2 + 5x + b, then show that a = b
