Question

What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for  stitching margins and wastage in cutting is approximately 20 cm (Use it 𝜋 = 3.14)

Answer 1

Given that, 

Height of conical tent (h) =8m. 

Radius of base of tent (r) = 6m 

Slant height (l)`=sqrt(r^2+h^2)=sqrt(8^2+6^2)=sqrt100=10m` 

CSA of conical tent = `pirl=(3.14xx6xx10)m^2` 

`=188.4m^2` 

Let the length of tarpaulin sheet require be L 

As 200m will be wasted, So effective length will be (L-0.2m) 

Breadth of tarpaulin = 3m 

Area of sheet = CSA of sheet 

`(Lxx0.2mxx3)m=188.40m^2 ` 

`⇒ L-0.2m=62.8m ` 

⇒ L=63m 

Thus, the length of the tarpaulin sheet will be =163m .