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प्रश्न
What is the value of \[\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}}\sin^{2}x\,dx\]?
पर्याय
\[\frac{\pi}{6}\]
\[\frac{\pi}{12}\]
\[\frac{\pi}{4}-\frac{1}{2}\]
\[\frac{\pi}{4}+\frac{1}{2}\]
MCQ
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उत्तर
Use \[\sin^{2}x=\frac{1-\cos 2x}{2}\] after applying the even-function property. The resulting value is \[\frac{\pi}{4}-\frac{1}{2}\].
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