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प्रश्न
What is the value of \[\int\sin^3x\cos^2x\,dx\]?
पर्याय
\[\frac{1}{3}\cos^3x-\frac{1}{5}\cos^5x+C\]
\[-\frac{1}{3}\cos^3x+\frac{1}{5}\cos^5x+C\]
\[-\frac{1}{3}\sin^3x+\frac{1}{5}\sin^5x+C\]
\[\frac{1}{3}\cos^3x+\frac{1}{5}\cos^5x+C\]
MCQ
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उत्तर
The transformed integral is \[-\int(t^2-t^4)\,dt\]. Integrating and substituting \[t=\cos x\] gives the stated result.
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