Advertisements
Advertisements
प्रश्न
What is the smallest number that when divided by three numbers such as 35, 56 and 91 leaves remainder 7 in each case?
Advertisements
उत्तर
35 = 5 × 7
56 = 2 × 2 × 2 × 7
91 = 7 × 13
L.C.M. of 35, 56, 91 = 5 × 7 × 2 × 2 × 2 × 13 = 3640
∴ Required number = 3647 which leaves remainder 7 in each case.
APPEARS IN
संबंधित प्रश्न
Given that HCF (306, 657) = 9, find LCM (306, 657).
Check whether 6n can end with the digit 0 for any natural number n.
Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers.
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = Product of the two numbers.
26 and 91
Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where, m, n are non-negative integers.\[\frac{13}{125}\]
Find the LCM and HCF of the following pair of integers and verify that LCM × HCF = product of the two numbers.
336 and 54
Find the greatest number consisting of 6 digits which is exactly divisible by 24, 15, 36?
The largest number which divides 60 and 75, leaving remainders 8 and 10 respectively, is ______.
The least number that is divisible by all the numbers from 1 to 10 (both inclusive) is ______.
(HCF × LCM) for the numbers 30 and 70 is ______.
