Advertisements
Advertisements
प्रश्न
What is the smallest number that when divided by three numbers such as 35, 56 and 91 leaves remainder 7 in each case?
Advertisements
उत्तर
35 = 5 × 7
56 = 2 × 2 × 2 × 7
91 = 7 × 13
L.C.M. of 35, 56, 91 = 5 × 7 × 2 × 2 × 2 × 13 = 3640
∴ Required number = 3647 which leaves remainder 7 in each case.
APPEARS IN
संबंधित प्रश्न
Given that HCF (306, 657) = 9, find LCM (306, 657).
Find the LCM and HCF of the following integers by applying the prime factorisation method:
40, 36 and 126
Find the LCM and HCF of the following integers by applying the prime factorisation method:
24, 15 and 36
The HCF of two numbers is 145 and their LCM is 2175. If one number is 725, find the other.
Express the number as a product of its prime factor:
156
If m, n are natural numbers, for what values of m, does 2n × 5m ends in 5?
LCM of the given number ‘x’ and ‘y’ where y is a multiple of ‘x’ is given by ______.
(HCF × LCM) for the numbers 70 and 40 is ______.
The HCF of the smallest 2-digit number and the smallest composite number is ______.
The HCF of two numbers 65 and 104 is 13. If LCM of 65 and 104 is 40x, then the value of x is ______.
