Advertisements
Advertisements
प्रश्न
What is the peak current in a capacitor connected to an AC source?
पर्याय
\[i_m=\omega Cv_m=v_mX_C\]
\[i_m=\omega Cv_m=\frac{v_m}{X_C}\]
\[i_m=\frac{Cv_m}{\omega}=v_mX_C\]
\[i_m=\frac{\omega v_m}{C}=\frac{v_m}{X_C}\]
MCQ
Advertisements
उत्तर
The amplitude of \[i=\omega Cv_m\cos\omega t\] is \[\omega Cv_m\]. Using capacitive reactance, the same peak current is \[\frac{v_m}{X_C}\].
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
