Question

What is the molality of the solution of a certain solute in a solvent, if there is a freezing point depression of 0.184°C and if the freezing point constant is 18.4°C m⁻¹?

पर्याय

• 0.01

• 1.0

• 0.001

• 100

Answer 1

0.01

Explanation:

Given: Depression of freezing point (ΔT_f) = 0.184°C

Freezing point constant (K_f) = 18.4°C m⁻¹

We know that,

ΔT_f = K_f · m

m = `(ΔT_f)/K_f`

= `0.184/18.4`

= 0.01 mol/kg