Question

What is the final current equation for a pure resistor AC circuit?

पर्याय

• \[i=I_{\mathrm{rms}}^{2}R\]

• \[i=i_m\sin 2\omega t\]

• \[i=i_m\cos\omega t\]

• \[i=i_m\sin\omega t\]

Answer 1

Using \[i_m=\frac{v_m}{R}\] in \[i=\frac{v_m}{R}\sin\omega t\] gives \[i=i_m\sin\omega t\]. Current and applied voltage have the same sinusoidal time factor.