Question

What is the electron’s de Broglie wavelength when its momentum magnitude is \[mv_n\]?

पर्याय

• \[\lambda=\frac{h}{mv_n}\]

• \[\lambda=\frac{nh}{mv_n}\]

• \[\lambda=\frac{h}{mv_nr_n}\]

• \[\lambda=\frac{mv_n}{h}\]

Answer 1

Substituting \[p=mv_n\] into \[\lambda=\frac{h}{p}\] gives \[\lambda=\frac{h}{mv_n}\]. This wavelength is used in the standing-wave condition for a circular orbit.